3x^2-2x-94=0

Solution for 3x^2-2x-94=0 equation:

3x^2-2x-94=0

a = 3; b = -2; c = -94;
Δ = b2-4ac
Δ = -22-4·3·(-94)
Δ = 1132
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1132}=\sqrt{4*283}=\sqrt{4}*\sqrt{283}=2\sqrt{283}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{283}}{2*3}=\frac{2-2\sqrt{283}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{283}}{2*3}=\frac{2+2\sqrt{283}}{6}
$